Percentages
Q.
1. The
difference between 78% of a number and 59% of the same number is 323. What is
62% of that number?
(a) 1071
(b) 1173 (c) 1037 (d) 1159 (e) None of these
Ans:
(e) None of these
Explanation:
The difference in percentage = 78% - 59% = 19%
i.e. 19% of a number = 323
therefore,
62% of the number = 323 × 62/19 = 1054.Ans.
Q.
2. 88%
of a number is 35640. What is 65% of that number?
(a) 25920
(b) 26500 (c) 26325 (d) 26730 (e) None of these
Ans:
(c) 26325
Explanation:
88% of a number = 35640
Therefore, 65% of that number = 35640 × 65/88 =
26325. Ans.
Q.
3. Tanya
obtained 95% marks in Physics, Chemistry and Maths together and she obtained
225 marks in Social Science, English and Hindi together. If the maximum marks
one can obtain in each of the subjects is 100, what is Tanya’s overall
percentage in all the six subjects together?
(a) 80
(b)75 (c) 90 (d) 95
(e) None of these
Ans:
(e) None of these
Explanation:
Maximum marks in each subject = 100
So, his total marks in Physics, Chemistry and Maths
= 95% of 300 = 285
Total marks obtained in Social Science, English and
Hindi = 225 out of 300
Therefore, total marks in 6 subjects = 285 + 225 =
510
So, the required percentage = 510 × 100/600 = 85%. Ans.
Q.
4. 40%
of 60% of 3/5th of a number
is 504. What is 25% of 2/5th of that number?
(a) 180 (b)
175 (c) 360 (d) 350
(e) None of these
Ans: (d) 350
Explanation:
Let
‘x’ be the number.
Then, 40/100 × 60/100 × 3/5 × x = 504
144x = 504 × 1000
Therefore, x = 504 × 1000/144 = 3500
Then, 25/100 × 2/5 × 3500 = 350. Ans.
Q.
5. In
a test consisting of 80 questions carrying one mark each, Arpita answers 65% of
the first 40 questions correctly. What percent of the other 40 questions does
she need to answer correctly to score 75% on the entire test?
(a) 60 (b)
80 (c) 75 (d) 40
(e) None of these
Ans:
(e) None of these
Explanation:
Total marks
for 80 questions = 80
75% of 80 = 60
65% of 40 = 26
Required marks for other 40 questions = 60 – 26 =
34 out of 40
Therefore, the required percentage = 34 × 100/40 =
85%. Ans.
Q.
6. A
sum of Rs.2236 is divided among A, B and C such that A receives 25% more than C
and C receives 25% less than B, what is A’s share in the amount?
(a) Rs. 460
(b) Rs. 890 (c) Rs. 780 (d) Rs.1280
(e) None of these
Ans:
(c) Rs.780
Explanation:
C = 75 B/100 = 3 B/4
and so, A = 125 × 3 B/100 × 4 =
15 B/16
Then, 15 B/16 + 3 B/4 + B = 2236
i.e. 43 B/16 = 2236
and B = 2236 × 16/43 = 832
Therefore, A’s amount = 15 × 832/16 =Rs.780.Ans.
Q.
7. (7.9%
of 134) – (3.4% of 79) = ?
(a) 8.1 (b)
7.8 (c) 8.6 (d) 7.3
(e) None of these
Ans:
(e) None of these
Explanation:
7.9 ×134/100 – 3.4 × 79/100 = 10.586 – 2.686 = 7.9. Ans.
Q.
8.
In a class of 65 students and 4 teachers, each student got sweets that are 20%
of the total number of students and each teacher got sweets that are 40% of the
total number of students. How many sweets were there?
(a) 845 (b)
897 (c) 949 (d) 104
(e) None of these
Ans:
(c) 949
Explanation:
No. of sweets
each student get = 20% of 65 = 13
No. of sweets each teacher get = 40% of 65 = 26
No. of sweets distributed to 65 students = 13 × 65 = 845
No. of sweets distributed to 4 teachers = 4 × 26 =
104
Therefore, the total no. of sweets there = 845 + 104
= 949. Ans.
Q.
9. What
is 35% of 42 % of 6/7th of 500?
(a) 36 (b)
44 (c) 52 (d) 60
(e) None of these
Ans: (e) None of these
Explanation:
35/100 × 42/100 × 6/7 × 500 = 63. Ans.
Q.
10. 88.25%
of 450 = ?% of 530
(a) 70 (b)
68 (c) 75 (d) 80
(e) 65
Ans:
(c) 75
Explanation:
88.25 × 450/100 = ? × 530/100
i.e. 88.25 × 450
= ? × 530
:. ? = 88.25 × 450/530 = 75.15 = 75 approximately. Ans.
Q.
11. ?%
of 450 + 46% of 285 = 257.1
(a) 34 (b)
32 (c) 21 (d)
28 (e) None of these
Ans:
(d) 28
Explanation:
? × 450/100 + 46 × 285/100 = 257.1
? × 450 + 46
× 285/100 = 257.1
? × 450 + 46 × 285 = 25710
? × 450 = 25710 – 13110 = 12600
? = 12600/450 = 28 Ans.
Q.
12. 75%
of 280 – 24% of 45 = ?
(a) 194.5
(b) 195 (c) 199.2 (d) 198
(e) None of these
Ans:
(c) 199.2
Explanation:
75% of 280 = 280 × ¾ = 210
24% of 45 = 25% of 45 – 1% of 45
= 25/4 - .45 = 11.25 - .45 = 10.80
Therefore, ? = 210 – 10.80 =199.2. Ans.
Q.
13. 5040
÷ ( ?% of 840) = 8
(a) 45 (b)
60 (c) 75 (d) 50
(e) None of these
Ans:
(c) 75
Explanation:
5040 ÷ ? × 840/100 =8
5040 × 100 /? × 840 = 8
? = 5040 × 100/8 × 840 =75. Ans.
Q.
14. The
18% of a number is 59.04. what is 25% of that number?
(a) 76 (b)
82 (c) 68 (d) 91
(e) None of these
Ans:
(b) 82
Explanation:
18% = 59.04
1% = 59.04/18
25% of the number = 59.04 × 25/18 = 82. Ans.
Q.
15. Three
–fifth of a number is 168. What is 12% of that number?
(a) 35.4 (b)
34.2 (c) 36.4 (d) 33.6
(e) None of these
Ans:
(d) 33.6
Explanation:
3/5th of
the number = 168
So, the number = 168 × 5/3 = 280
12% of 280 = (10% + 2%) of 280 = 28 + 5.6 = 33.6.Ans.
Q.16.
38%
of 341 = ?
(a) 120.68
(b) 129.58 (c) 135.78 (d) 136.28
(e) None of these
Ans:
(b) 129.58
Explanation:
38% of 341 = (3 × 10% + 8%) of 341
= 3 × 34.1 + 8 × 3.41 (where 1% = 3.41)
= 102.3 + 27.28 =129.58.Ans.
Q.
17. Out
of 820 employees in an organization 20% of the employees got promoted to a
higher grade. How many employees did not get promoted?
(a) 680 (b)
668 (c) 656 (d) 674
(e) None of these
Ans:
(c) 656
Explanation:
The no. of employees did not get promoted = 80% of 820
= 8 × 10% of 820 = 8 × 82 = 656.Ans.
Q.
18. 96%
of a number is 19584. What is 56% of that number?
(a) 11016
(b)11222 (c) 11628 (d) 10812 (e) None of these
Ans:
(e) None of these
Explanation:
Because 96% = 19584
1% = 19584/96
Then 56% of that number = 19584 × 56/96 = 11424.Ans.
Q.
19. 16%
of 380 × 5 = ?
(a) 276
(b)284 (c) 304 (d) 312
(e)None of these
Ans:
(c)304
Explanation:
16% of 380 = (10% + 5% + 1%) of 380
= 38 + 19 + 3.8 = 60.8
16% of 380 × 5 = 60.8 × 5 = 304.Ans.
Q.20.
4550
÷ 25% of ? = 130
(a) 145 (b) 140
(c) 125 (d) 160 (e) None of these
Ans:
(b) 140
Explanation:
4550 ÷ 25 ?/100 =130
4550 × 100/25? =130
? = 4550 × 100/25 × 130 = 140. Ans.
Q.21.
(550%
of 250) ÷ 275 = ?
(a)15 (b)1.5 (c)0.5
(d) 25 (e) None of these
Ans:
(e) None of these
Explanation:
550% of 250 = (5 × 100% + 50%) of 250
= 1250 + 125 = 1375
1375/275 = 5. Ans.
Q.
22. 155
of 45% of a number is 105.3. What is 24%
of that number?
(a) 385.5
(b)374.4 (c) 390 (d)375
(e) None of these
Ans:
(b) 374.4
Explanation:
15/100 × 45/100 × x = 105.3
Then, x = 105.3 × 100 × 100/ 15 × 45 = 1560
24% of 1560 = (20% + 4%) of 1560
= 312 + 62.4 = 374.4. Ans.
Q.
23. 135%
of 480 + ?% of 320 = 728
(a) 25 (b)
28 (c) 125 (d) 115
(e) None of these
Ans:
(a) 25
Explanation:
135% of 480 = (100% + 3× 10% + 5%) of 480
= 480 + 144 + 24 = 648
?/100 ×320 = 728 – 648
? = 80 ×
100/320 = 25.Ans.
Q.
24. 64%
of a number is 2592. What is 88% of that number?
(a) 3458 (b)
3202 (c) 3826 (d) 3564
(e) None of these
Ans:
(d) 3564
Explanation:
64% = 2592
So, 1% = 2592/64
88% of the same number = 2592 × 88/64 = 3564.Ans.
Q.
25. The
difference between 54% of a number and 26% of the same number is 22526. Whaat
is 66% of that number?
(a) 53097 (b)
48372 (c) 51218 (d) 49124
(e) None of these
Ans:
(a) 53097
Explanation:
The difference in percentage i.e. 54% - 26% = 28%
Given that 28% = 22526
1% = 22526/28
66% of the same number = 22526 × 66/28 = 53097.Ans.
Q.
26. 30%
of 15.6 + ? = 40% of 30
What is the value of question mark in the above
equation?
(a) 6.32 (b) 7.32
(c) 8.32 (d) 5.32 (e) None of these
Ans:
(b) 7.32
Explanation:
30% of 15.6 = 3 × 1.56 = 4.68
40% of 30 = 4 × 3 =12
Given that 4.68 + ? = 12
Therefore, ? = 12 – 4.68= 7.32. Ans.
Q.
27. The
difference between 90% of a number and 83% of the same number is 175. What is
99% of that number?
(a) 2420 (b)
2475 (c) 2500 (d) 1750
(e) None of these
Ans:
(b) 2475
Explanation:
The difference in percentage = 90% - 83% = 7%
Given that 7% = 175
So, 1% = 175/7
99% of the same number = 175 × 99/7 = 2475.Ans.
Q.
28. 45%
of 90 = ?% of 81
(a) 405 (b)
500 (c) 50 (d) 28.5
(e)None of these
Ans:
(c) 50
Explanation:
45% of 90 = (50% - 5%) of 90
= 45 – 4.5 = 40.50
i.e. 40.5 = ?/100 × 81
? = 40.5 × 100/81
= 50.Ans.
Q.
29.
15% of 15 = ?
(a) 2.25 (b)
22.5 (c) 0.15 (d) 0.25
(e) None of these
Ans:
(a) 2.25
Explanation:
15% of 15 = (10% + 5%) of 15
= 1.5 + .75 = 2.25. Ans.
Q.
30. The
value of 7/10 of 3/17 of 30% of 425 is
equal to
(a) 13.5 (b)
24.25 (c) 15.75 (d) 16
(e) None of these
Ans:
(c) 15.75
Explanation:
30% of 425 = 3 × 10% of 425 = 127.5
7/10 × 3/17 × 127.5 = 63/4 = 15.75.Ans.+
Q.
31. 36%
of 182 + 177% of 36 = ?
(a) 125 (b)
130 (c) 135 (d) 140
(e) 170
Ans:
(b) 130
Explanation:
36% of 182 = ( 3 × 10%
+ 5% + 1) of 182
= 3 × 18.2 + 9.1 + 1.82 = 54.6 + 9.1 + 1.82 = 65.52
177% of 36 = (100% +
75% + 2%) of 36 = 36 + 27 + .72 = 63.72
Therefore, the required
sum = 65.52 + 63.72 = 129.24 = 130 approximately. Ans.
Q.
32. Because
of decrease of available manpower a toy factory reduced its monthly output by
20%. What should be the percent increase of manpower to bring the production up
to normal?
(a) 16 2/3 (b) 24
(c) 20 (d) 25 (e) None of these
Ans:
(d) 25%
Explanation:
The reduced out put =
80%
Therefore, the increase
in manpower required in percentage = 20 × 100/80 = 25%. Ans.
Q.
33. Vaishali
spent Rs.31897 on the air-conditioner for her home, Rs.38789 on buying plasma
television and the remaining 23% of the total amount she had as cash with her.
What was the total amount?
(a) Rs.74625 (b) Rs.86750 (c) Rs.91800 (d) Cannot be determined (e) None of these
Ans:
(c) Rs.91800
Explanation:
The total amount
she spent = Rs.31897 + Rs.38789 =
Rs.70686
Percentage of amount
she spent = 100 – 23 = 77 % i.e. 77% = 70686
Therefore, the total
amount = 70686 × 100/77 = Rs.91800. Ans.
Q.
34.
40% of 250 = 50% of ?
(a) 200 (b) 100
(c) 150 (d) 400 (e) None of these
Ans:
(a) 200
Explanation:
40% of 250 = (50% - 10%
0 of 250 = 125 – 25 = 100
Given that, 100 = 50
?/100
? = 10000/50 = 200. Ans
Q.
35.
In an examination it is required to get 40% of the aggregate marks to pass. A
student gets 265 marks and is declared fail by 55 marks. What is the maximum
aggregate marks a student can get?
(a) 800 (b) 750
(c) 650 (d) Cannot be
determined (e) None of these
Ans:
(a) 800
Explanation:
265 + 55 = 320 = 40% of
the aggregate marks
Therefore, the
aggregate marks = 320 × 100/40 = 800. Ans.
Q.
36. The
difference between 75% of a number and 20% of the same number is 378.4. What is 40% of that number?
(a) 275.2 (b) 274
(c) 267.2 (d) 266 (e) None of these
Ans:
(a) 275.2
Explanation:
The difference in
percentage i.e. 75% - 20% = 55%
55% of a number = 378.4
Therefore, 1% of the
number = 378.4/55
And 40% of the same
number = 378.4 × 40/55 = 275.2. Ans.
Q.
37. The difference between 56% of a number and
39% of the same number is 425. What is 63% of that number?
(a) 1525 (b) 1650
(c) 1700 (d) 1575 (e) None of these
Ans:
(d) 1575
Explanation:
The difference in
percentage i.e. 56% - 39% = 17%
17% of the number = 425
Therefore, 1% = 425/17
= 25
So, 63 % of the number
= 25 × 63 = 1575. Ans.
Q.
38. 60
per cent of first number is 40 per cent of the second number. What is the
respective ratio of the first number to the second number?
(a) 2 : 3 (b) 21
: 31 (c) 7 : 10 (d) cannot be determined (e) None of these
Ans:
(a) 2 : 3
Explanation:
Let the numbers be ‘a’
and ‘b’
60a/100 = 40b/100
60a = 40b
Then, a : b = 40 : 60
= 2 : 3. Ans.
Q.
39. 82%
of 850 – (?)² = 16²
(a) 30 (b) 27
(c) 24 (d) 21 (e) None of these
Ans:
(d) 21
Explanation:
82% of 850 = (8 × 10% +
2%) of 850
= 680 + 17 = 697
i.e. 697 – 256 = ?²
441 = 21² = 21.Ans.
Q.
40. 40%
of 15% of 3/4th of a number is 153. What is the number?
(a) 3400 (b) 3650
(c) 3600 (d) 3200 (e) None of these
Ans:
(a) 3400
Explanation:
Let ‘x’ be the number
Then, 40/100 × 15/100 ×
¾ × x = 153
So, x = 153 × 100 × 100 × 4/40 × 15 × 3 = 3400.Ans.
Q.
41. 185%
of 400 + 35% of 240 = ?% of 1648
(a) 85 (b) 75
(c) 125 (d) 50 (e) None of these
Ans:
(d) 50
Explanation:
185% of 400 = (100% + 8
× 10% + 5%) of 400
= 400 + 320 + 20 = 740
35% of 240 = (3 × 10% +
5%) of 240 = 72 + 12 = 84
740 + 84 = 824
Given that, 824 = ?/100 × 1648
? = 824 × 100/1648 =
50. Ans.
Q.
42. 15%
of ? = 94.5
(a) 14.175 (b) 1410
(c) 630 (d) 141 (e) None of these
Ans:
(c) 630
Explanation:
15 ?/100 = 94.5
? = 94.5 × 100/15 =
630. Ans.
Q.
43. 63%
of a number is 2583. What is 45% of that number?
(a) 1845 (b)
1763 (c) 2255 (d) 1927
(e) None of these
Ans:
(a) 1845
Explanation:
63% = 2583
Then, 1% = 2583/63
45% = 2583 × 45/63 = 1845.
Ans.
Q.
44. What
is 240 per cent of 700?
(a) 1650 (b) 1780
(c) 1560 (d) 1710 (e) None of these
Ans:
(e) None of these
Explanation:
240% = 2 × 100% + 4 ×
10%
240% of 700 = 2 × 700 + 4 × 70 = 1680 Ans.
Q.
45. What
is 30% of 25% of 3/5th of 9800?
(a) 433
(b) 453 (c) 441 (d) 391
(e) None of these
Ans:
(c) 441
Explanation:
30/100 × 25/100 × 3/5 ×
9800 = 441.Ans.
Q.
46. Sameera
wove a sweater buying wool for Rs.375. She sold it for Rs.300. Calculate her
loss per cent.
(a) 35% (b) 25%
(c) 20% (d) 15% (e) None of these
Ans:
(c) 20%
Explanation:
Percentage loss/gain =
Actual loss/ gain × 100/ Cost
Actual loss = 375 – 300
= Rs.75
So, Percentage loss =
75 ×100/375 = 20%. Ans.
Q.
47. ? ÷ 6 = 30% of 860
(a) 1548 (b) 1624
(c) 17208 (d) 1428 (e) None of these
Ans:
(a) 1548
Explanation:
?/6 = 30 × 860/100
? = 30 × 860 × 6/100 =
1548. Ans.
Q.
48. Ramu
gave 35% of the amount he had to
Shakeel. Shakeel in turn gave two-thirds of what he received from Ramu to
Joseph. After spending Rs.150 on lunch out of the amount he got from Shakeel,
Joseph now has Rs.550 left with him. How much amount did Ramu have?
(a) Rs.2800 (b) Rs.2000
(c) Rs.3000 (d) Can’t be
determined (e) none of these
Ans:
(c) Rs.3000
Explanation:
The amount given by
Shakeel to Joseph = 150 + 550 = Rs.700
This is 2/3rd
of the amount given to Shakeel by Ramu and let the amount got by Shakeel = ‘x’
i.e. 2/3 × x = 700
Therefore, the amout
given to Shakeel by Ramu , x = 700 × 3/2 = Rs.1050
Rs. 1050 is 35% of
amount Ramu had
So, the Total amount
Ramu had = 1050 × 100/35 = Rs.3000.Ans.
Q.49.
What
is the 30% of 40% of 2/5th of 2500?
(a)500 (b) 400
(c) 360 (d) 120 (e) None of these
Ans:
(d) 120
Explanation:
30/100 × 40/100 × 2/5
× 2500 = 120.Ans.
Q.
50. Two
numbers are less than the third number by 50% and 54% respectively. By how much
per cent is the second number less than the first number?
(a) 13 (b) 10
(c) 12 (d) Cannot be
determined (e) None of these
Ans:
(e) None of these
Explanation:
Let the third number be
‘100’
Then the first number =
100 – 50 = 50
The second number = 100
– 54 = 46
The difference between
the first and the second number = 50 – 46 = 4
Therefore, the required
percentage = 4 × 100/50 =8. Ans.
Q.
51. If
the numerator of a fraction is increased by 200% and the denominator is
increased by 300%, the resultant fraction is 15/26. What was the original
fraction?
(a) 8/11 (b) 10/11
(c) 9/13 (d) 10/13 (e) None of these
Ans:
(d) 10/13
Explanation:
Let x/y be the original
fraction
Then, x + 2x/100 / y +
3y/100 = 15/26
i.e. x + 2x/y + 3y =
15/16
3x/4y = 15/26
x/y = 15 × 4/26 × 3 =
10/13. Ans.
Q.
52. One
– fifth of a number is 81. What will 68% of that number be?
(a) 195.2 (b) 275.4
(c) 225.6 (d) 165.8 (e) None of these
Ans:
(b) 275.4
Explanation:
Let ‘x’ be the number
Then, x/5 = 81
So, x = 81 × 5 = 405
68% = 50% + 10 % + 8 ×
1%
68% of 405 = 202.5 +
40.5 + 32.4 = 275.4 Ans.
Q.
53. In
an examination, 1100 boys and 900 girls appeared. 50% of the boys and 40% of
the girls passed. The percentage of failed candidates is
(a) 45.0 (b) 45.5
(c) 54.5 (d) 59.2 (e) None of these
Ans:
(c) 54.5
Explanation:
No. of failed boys =
550
No. of failed girls =
540
Therefore, total number
of failed candidates = 1090
So, the required
percentage = 1090 × 100/2000 = 54.5 Ans.
Q.
54. 56%
of a number is less than its 72% by 56. What is 70% of that number?
(a) 300 (b) 235
(c) 240 (d) 350 (e) None of these
Ans:
(e) None of these
Explanation:
i.e. 72 – 56 = 16 % of
the number = 56
1% of the number =
56/16
Then, 70% of the number
= 56 × 70/16 = 245. Ans.
Q.
55. Five
– sixth of a number is 720. What will 45% of that number be?
(a) 346.6 (b) 388.8
(c) 392.2 (d) 344.4 (e) None of these
Ans:
(b) 388.8
Explanation:
Let ‘x’ be the number
Then, 5x/6 = 720
So, x = 720 × 6/5 = 864
45% = 50% - 5%
45% of 864 = 432 – 43.2
= 388.8.Ans.
Q.
56. In an
examination it is required to get 380 of the aggregate marks to pass. A student
gets 32% marks and is declared failed by 76 marks. What are the maximum
aggregate marks a student can get?
(a) 945 (b) 975
(c) 950 (d) Cannot be
determined (e) None of these
Ans:
(c) 950
Explanation:
32% of the total marks
= 380 – 76 = 304
Therefore, 1% of the
total marks = 304/32
So, the total marks a
student can get = 304 × 100/32 =950. Ans.
Q.
57. One
– seventh of a number is 51. What will be 64% of that number?
(a) 248.12 (b) 228.48
(c) 238.24 (d) 198.36 (e) None of these
Ans:
(b) 228.48
Explanation:
Let ‘x’ be the number
Then, x = 51 × 7 = 357
64% = 50% + 10% + 1% ×
4
So, 64% of 357 = 178.5
+ 35.7 + 14.28 = 228.48 Ans.
Q.
58. The
difference between 56% of a number and 41% of the same number is 660. What is
8% of that number?
(a) 321 (b) 336
(c) 345 (d) 358 (e) None of these
Ans:
(e) None of these
Explanation:
56 – 41 = 15% of the
number = 660
Therefore, 1% of the same
number = 660/15
And so, 8% of the number = 660 × 8/15 = 352.Ans.
Q.
59. A
cricketer has batted in 105 innings. He has scored 17 centuries, crossed the
50- run mark 28 times and crossed the 25-run mark 39 times. The no. of times he
has scored below 25 is what percentage of the number of times he scored between
25 and 49 ( both 25 and 49 included)?
(a) 450% (b) 600%
(c) 500% (d) cannot be determined
(e) None of these
Ans:
(b) 600%
Explanation:
The no. of times he
crossed above 25-run mark = 39
So, the no. of times he
crossed below the 25 – run mark = 105 – 39 = 66 times
The no. of times he
crossed above 50 – run mark = 28
Therefore, the no. of
times he crossed in between 25-run mark and 50-run mark = 39-28 = 11
Therefore the required
percentage = 66 × 100/11 = 600%. Ans.
Q.
60. 25%
of 50% of a number is 385. What is the number?
(a) 3050 (b) 3100
(c) 3004 (d) 3080 (e) None of these
Ans:
(d) 3080
Explanation:
25% = ¼; 50% = ½,
and let the number be ‘x’
i.e. ¼ × ½ × x = 385
Therefore, x = 385 × 4
× 2 = 3080. Ans.
Q.
61. Samir
secured 580 marks out of a total of 750 in an examination. What is Samir’s
approximate percentage in the exam?
(a) 81 (b) 77
(c) 71 (d) 75 (e) 84
Ans:
(b) 77
Explanation:
Required percentage =
580 × 100/750 = 77.3% = 77 approximately. Ans.
Q.
62. What
is 160% of 480?
(a) 768 (b) 684
(c) 786 (d) 864 (e) None of these
Ans:
(a) 768
Explanation:
160% = 100% + 50% + 10%
160% of 480 = 480 = 240
+ 48 = 768. Ans.
Q.
63. 15%
of the total number of students in a college play football. How many students
do not play football, if the total number of students in the college is 6500?
(a) 975 (b) 5525
(c) 910 (d) 5590 (e) None of these
Ans:
(b) 5525
Explanation:
15% = 10% + 5%
15 % of 6500 = 650 +
325 = 975
Therefore, the no. of
students who do not play football = 6500
– 975 = 5525.Ans.
Q.
64. 75%
of a number is equal to four – fifths of another number. What is the ratio
between the first number and the second number?
(a) 5 : 3 (b) 15 : 16
(c) 3 : 5 (d) 16 : 15 (e) None of these
Ans:
(d) 16 : 15
Explanation:
Let the two numbers be
‘x’ and ‘y’
Then, 75x/100 = 4y/5
5 × 75x = 4 × 100y
x/y = 400/375 = 16 :
15. Ans.
Q.
65. Sunil
scored 54 percent marks in a test. Ravi scored 450 marks in the same test which
is 300 less than Sonu. Sunil’s score is 60 more than Sonu. If Ram scored 900
marks in the test, what is Ram’s percentage?
(a) 80 (b) 65
(c) 75 (d) 60 (e) None of these
Ans:
(d) 60
Explanation:
Sonu’s score = 450 +
300 = 750
Sunil’s score = 54% of
the total = 750 + 60 =810
Then, the maximum marks
= 810 × 100/54 = 1500
Therefore, the required
percentage = 900/1500 × 100 = 60%. Ans.
Q.
66. In
a school there are 800 students out of whom 45 percent are girls. Monthly fee
of each boy is Rs.600 and monthly fee of each girl is 30 percent less than each
boy. What is the total monthly fee of girls and boys together?
(a) Rs.425400 (b) Rs.414600 (c) Rs.419600 (d) Rs.423400 (e) None of these
Ans:
(e) None of these
Explanation:
No. of boys = 55% of
800 = 440
No. of girls = 800 –
440 = 360
Total monthly fee of
boys = 440 × 600 = 264000
Total monthly fee of
girls = 360 × 70% of 600 = 360 × 420 = 151200
Therefore, the total
monthly fee of boys and girls = 264000 + 151200 = Rs.415200.Ans.
Q.
67. While
selling a watch, a shopkeeper gives a discount of 15%. If he gives a discount
of 20%, he earns Rs.51 less as profit. What is the original price of the watch?
(a) Rs.920 (b) Rs.985 (c) Rs.1125 (d) Rs.1020 (e) None of these
Ans:
(d) Rs.1020
Explanation:
The difference in
percentage, i.e. 20% - 15% = 5% = Rs.51
That is, Rs.51 is 5% of
the original price of the watch
Therefore, the original
price of the watch = 51 ×100/5 =
Rs.1020.Ans.
Q.
68. Five-ninth
of a number is equal to twenty five per cent of second number. Second number is
equal to one-fourth of third number. The value of third number is 2960. What is
30% of first number?
(a) 88.8 (b) 99.9
(c) 66.6 (d) cannot be
determined (e) None of these
Ans:
(b) 99.9
Explanation:
Let a, b, and c be the
three numbers
Then, b = c/4
5a/9 = 25c/4/100, i.e. 5a/9 = 25c/400
5a × 400 = 9 × 25c
2000a = 225c ( given, c = 2960)
Therefore, a = 225 ×
2960/2000 = 333
So, 30% of a = 3 × 10%
of a
= 3 × 33.3 = 99.9.Ans.
Q.
69. What
is 28% of 36% of 5/7th of 5000?
(a) 480 (b) 375
(c) 360 (d) 420 (e) None of these
Ans:
(c) 360
Explanation:
28/100 × 36/100 × 5/7 ×
5000 = 360. Ans.
Q.
70. In
a class of 50 students and 5 teachers, each student got sweets that are 12% of
the total number of students and each teacher got sweets that are 20% of the
total number of students. How many sweets were there?
(a) 345 (b) 365
(c) 330 (d) 350 (e) None of these
Ans:
(d) 350
Explanation:
50 × 12 × 50/100 + 5 × 20
× 50/100 = 300 + 50 = 350.Ans.
Q.
71. If
the numerator of a fraction is increased by 500% and the denominator is
increased by 300%, the resultant fraction is 1 1/17. What was the original
fraction?
(a) 12/17 (b) 13/17
(c) 3/7 (d) 4/11 (e) None of these
Ans:
(a) 12/17
Explanation:
Let x/y be the original
fraction
Then, x + 5x/y + 3y =
18/17 (i.e. 500% of x = 5x,
& 300% of y = 3y)
That is, 6x /4y =
18/17 i.e. 102x = 72y
Then, x/y = 72/102 =
24/34 = 12/17. Ans.
Q.
72. One-fifth
of a number is 62. What will 73% of that number be?
(a) 198.7 (b) 212.5
(c) 226.3 (d) 234.8 (e) None of these
Ans:
(c) 226.3
Explanation:
Let ‘x’ be the number
Then, x/5 = 62
So, x = 62 × 5 = 310
73% = 50% + 2 × 10% + 3
× 1%
So, 73% of 310 = 155 +
62 + 9.3 = 226.3. Ans.
Q.
73. In
a class of 240 students, each student got sweets that are 15% of the total
number of students. How many sweets were there?
(a) 3000 (b) 3125
(c) 8640 (d) Cannot be
determined (e) None of these
Ans:
(c) 8640
Explanation:
Each student gets 15%
of 240 sweets, i.e. = 36 nos.
Therefore, the total
number of sweets = 240 × 36 = 8640. Ans.
Q.
74. 12%
of 840 × 0.25% of 148 = ?
(a) 37.296 (b) 101.17 (c) 68.432 (d) 97.046 (e) None of these
Ans:
(b) 101.17
Explanation:
12% of 840 = 100.8
.25% of 148 = .37
Required sum = 100.8 +
.37 = 101.17.Ans.
Q.
75. The
total number of students in the school are 4800, out of which 60% are girls.
What is the total number of boys in this school?
(a) 1920 (b) 1934
(c) 1980 (d) 1910 (d) None of these
Ans:
(a) 1920
Explanation:
The number of boys in
the school = 100 – 60 = 40% of 4800
= 4 × 10% of 4800
=
4 × 480 = 1920.Ans.
Q.
76. The
difference between 55% of a number and 25% of the same number is 11.10. What is
75% of that number?
(a) 27.75 (b) 37
(c) 21.25 (d) 45 (e) None of these
Ans:
(a) 27.75
Explanation:
The difference in
percentage, i.e. 55 -25 = 30%
30% of the number =
11.10
Therefore, 75% of that
number = 11.10 × 75/30 = 111/4 = 27.75. Ans.
Q.
77. In
an election between two candidates, one got 52% of the total valid votes. 25%
of the total votes were invalid. The total number of votes were 8400. How many
valid votes did the other person get?
(a) 3276 (b) 3196
(c) 3024 (d) Cannot be
determined (e) None of these
Ans:
(c) 3024
Explanation:
Number of valid votes =
75% of 8400 = 8400 × ¾ = 6300
Percentage of valid
votes got by other person = 48%
Therefore, the required
number of valid votes = 48% of 6300 = 4
× 10% + 5% + 3 × 1% of 6300
= 4 × 630 + 315 + 3 × 63
= 2520 + 315 + 189
=
3024.Ans.
Q.
78. Two-fifth
of a number is 182. What will 48% of that number be?
(a) 236.6 (b) 218.4
(c) 209.3 (d) 200.2 (e) None of these
Ans:
(b) 218.4
Explanation:
Let the number be ‘x’
Then, 2x/5 = 182
Then, x = 182 × 5/2 = 91
× 5 = 455
48% =50% - 2%
Therefore, 48% of 455 = 227.5 – 9.1 = 218.4. Ans.
Q.
79. In
a school there are 250 students out of whom 12 per cent are girls. Each girl’s
monthly fee is Rs.450/- and each boy’s monthly fee is 24 percent more than a
girl. What is the total monthly fee of girls and boys together?
(a) Rs.136620/- (b) Rs.136260/- (c) Rs.132660/- (d) Rs.132460/- (e)None of these
Ans:
(b) 136260/-
Explanation:
No. of girls = 12% of
250 = 30
No. of boys = 250 – 30
= 220
Total fee of 30 girls =
30 × 450 = Rs.13500/-
Fee for each boy = 450
+ 24% of 450
= 450 + 108 =
Rs.558
Total fee of 220 boys =
220 × 558 = Rs. 122760
Therefore, total
monthly fee of boys and girls in the school = 122760 + 13500 =Rs.136260/-. Ans.
Q.
80. Ravi
scored 225 marks in a test and failed by 15 marks. If the passing percentage of
passing the test is 25 per cent. What are the maximum marks of the test?
(a) 860 (b) 840
(c) 920 (d) 960 (e) None of these
Ans:
(d) 960
Explanation:
25% of the maximum
marks = 225 + 15 = 240
Therefore, maximum
marks = 240 × 4 = 960. Ans.
Q.
81. If
the height of a triangle is decreased by 40% and its base is increased by 40%
and its base is increased by 40%, what will be the effect on its area?
(a) No change (b) 16% increase (c) 8% decrease (d) 16% decrease (e) None of
these
Ans:
(d) 16% decrease
Explanation:
Let the base = 100 and
height = 100
Then the area of the
triangle = ½ × base × a height
=
100 × 100/2 = 5000
Now, the height is
decreased to 60 and the base is
increased to 140
Then, the area = 60×
140/2 =4200
The difference = 5000-
4200 = 800 decrease
Percentage effect on
its area = 800 × 100/5000 = 16% decrease. Ans.
Q.
82. An
HR Company employs 4800 people, out of which 45 per cent are males and 60 per
cent of the males are either 25 years or older. How many males are employed in
HR Company who are younger than 25 years?
(a) 2640 (b) 2160
(c) 1296 (d) 864 (e) None of these
Ans:
(d) 864
Explanation:
No. of males = 45% =
50% - 5%
= 2400 – 240 = 2160
The no. of employees
who are younger than 25 years = 40% of 2160
= 4 × 10% of 2160
= 4 × 216 = 864. Ans.
Q.
83. Six-eleventh
of a number is equal to twenty two per cent of second number. Second number is
equal to the one-fourth of third number. The value of the third number is 2400.
What is the 45% of first number?
(a) 109.8 (b) 111.7
(c) 117.6 (d) 123.4 (e) None of these
Ans:
(e) None of these
Explanation:
The third number = 2400
So, the second number =
2400/4 = 600
22% of 600 = 132
This 132 = 6/11 of
first number
Therefore, the first no. = 132 × 11/6 = 242
45% of 242 = 50% - 5%
of 242
= 121 – 12.1 = 108.9.Ans.
Q.
84. Two
– third of the first number is equal to the cube of the second number. If the
second number is equal to twelve per cent of 50. What is the sum of the first
and the second numbers?
(a) 330 (b) 360
(c) 390 (d) 372 (e) None of these
Ans:
(a) 330
Explanation:
Second number = 12% of
50 = 6
2/3 × First number
= 6³ = 216
First number = 216 ×
3/2 = 324
Then, the sum of first
and the second number = 324 + 6 = 330. Ans.
Q.
85. What
is the value of twenty four percent of four-ninth of five times square of
twenty seven?
(a) 388.8 (b) 376.8
(c) 378.6 (d) 346.6 (e) None of these
Ans:
(a) 388.8
Explanation:
24/100 × 4/9 × 5 × 27²
24/100 × 4/9 ×5 × 27 ×
27 = 388.8.Ans.
Q.
86. 14%
of 80 + ?% of 90 = 31.9
(a) 16 (b) 23
(c) 18 (d) 26 (e) None of these
Ans:
(b) 23
Explanation:
14% of 80 = 11.2
?% of 90 = 31.9 – 11.2
= 20.7
i.e. ?/100 × 90 = 20.7
? = 20.7 × 100/90 =
207/9 = 23%. Ans.
Q.
87. What
is the value of thirty eight per cent of seven-twelfth of twice the cube of
fifteen?
(a) 1496.25 (b) 1478.50 (c) 1649.25 (d) 1748.50 (e) None of these
Ans:
(a) 1496.25
Explanation:
38/100 × 7/12 × 2 ×
3375 = 1496.25. Ans.
Q.
88. Previously
the price of an article was Rs.460/- and now it has been increased to Rs.550/-.
What was the approximate per cent increase in the price of that article?
(a) 80 (b) 8
(c) 40 (d) 60 (e) 20
Ans:
(e) 20
Explanation:
The difference = Rs.90.
Therefore the
percentage increase = 90 × 100/460 = 20 approximately. Ans.
Q.
89. Two
numbers are greater than the third number by 40% and 48% respectively. By what
per cent is the second number greater than the first number?
(a) 42.17% (b) 57.14%
(c) 82.5% (d) 69% (e) 5.71%
Ans:
(e) 5.71%
Explanation:
Let the third number =
100
Then, the second no. =
148 and the first number = 140
The difference 148 –
140 = 8
So, the required
percentage = 8 /140 × 100 = 5.71%. Ans.
Q.
90. In an examination Sunil secured 480 marks
out of 1200 marks and failed by 96 marks. What is the minimum passing
percentage?
(a) 46 (b) 45
(c) 42 (d) 38 (e) None of these
Ans:
(e) None of these
Explanation:
Required marks for pass
= 480 + 96 = 576
Therefore, the minimum
passing percentage = 576 × 100/1200 = 48%. Ans.
Q.
91. Raman
scored 456 marks in an exam and Seeta got 54 percent marks in the same exam
which is 24 marks less than Raman. If the minimum passing marks in the exam is
34 per cent, then how much more marks did Raman score than the minimum passing
marks?
(a) 184 (b) 196
(c) 190 (d) 180 (e) None of these
Ans:
(a) 184
Explanation:
54% of the maximum
marks = 456 -24 = 432
Therefore, the maximum
marks = 432 × 100 /54 = 800
Then, the minimum
passing marks = 34 % of 800 = 272
The mark Raman scored
above the passing marks = 456 -272 = 184.
Ans.
Q.
92. If
a number is added to seven-ninth of thirty five percent of 900, the value so
obtained is 325. What is the number?
(a) 60 (b) 120
(c) 90 (d) 180 (e) None of these
Ans:
(e) None of these
Explanation:
Let ‘x’ be the number
7/9 × .35 × 900 + x =
325
Therefore, x = 325 –
245 = 80. Ans.
Q.
93. A
man sold a wristwatch for Rs.2400/- at a loss of twenty five percent. At what
rate should he have sold the wristwatch to earn a profit of twenty five per
cent?
(a) Rs.3600 (b) Rs. 4000 (c) Rs.3500
(d) Rs.3800 (e) None of these
Ans:
(b) Rs.4000
Explanation:
Rs.2400 is 75% of the
cost price of the wrist watch
Therefore, the cost
price = 2400 × 100/75 = Rs. 3200
To get a profit of 25%,
it should be sold at Rs.3200 + 25% of 3200
So, the required selling price = Rs. 3200 + 800 = Rs.4000. Ans.
Q.
94. Jasmine
scored 52 marks in Science, 36 marks in Hindi, 47 marks in English and 73 marks
in Sanskrit. The total marks of all the subjects together is 400. What is the
overall percentage of marks she got?
(a) 56 (b) 48
(c)45 (d) 52 (e) None of these
Ans:
(d) 52
Explanation:
The total marks scored
by Jasmine in four subjects out of 400 = 208
Therefore, the required
percentage = 208/400 × 100 = 52%. Ans.
Q.95.
35%
of a number is 182. What is 130% of that number?
(a) 676 (b) 667
(c) 673 (d) 663 (e) None of these
Ans:
(a) 676
Explanation:
1% of the number =
182/35
Therefore, 130% of the
same number = 182 × 130/35 = 26 × 26 = 676. Ans.
Q.
96. One-third
of a number is 96. What will 67% of that number be?
(a) 192.96 (b)
181.44 (c) 169.92 (d) 204.48
(e) None of these
Ans:
(a) 192.96
Explanation:
Let the number =x
Then, x = 3 × 96 = 288
67% = 50% + 10% + 5 % +
2 × 1%
Therefore, 67% of 288 =
144 + 28.8 + 14.4 + 5.76 = 192.96.Ans.
Q.
97. There
are 360 students in a class out of which 35% are day scholars. How many day
scholars are there in the class?
(a) 128 (b) 122
(c) 124 (d) 126 (e) None of these
Ans:
(d) 126
Explanation:
The no. of day scholars
= 35% of 360
= (3 × 10% + 5% ) of 360 = 3× 36 +
18 = 108 + 18
= 126. Ans.
Q.
98. In
an examination it is required to get 55% of the aggregate marks to pass. A
student got 340 and was declared failed by 5% marks. What are the maximum
aggregate marks a student can get?
(a) 650 (b) 660
(c) 680 (d) Cannot be
determined (e) None of these
Ans:
(c) 680
Explanation:
i.e. 50% of the
aggregate marks = 340
So, the aggregate marks
= 340 × 2 = 680. Ans.
Q.
99. The
sum of 35% of a number and 12% of the same number is 3055. What is the 72% of
that number?
(a) 4685 (b) 4680
(c) 4675 (d) 4670 (e) None of these
Ans:
(b) 4680
Explanation:
Let the number be ‘x’
Then, 35x/100 + 12x/100
= 3055
i.e. 35x + 12x/100
=3055
47x = 305500
So, x = 305500/47 =
6500
72 % = 50% + 2 × 10% +
2× 1%
Therefore, 72% of 6500
= 3250 + 1300 + 130 = 4680. Ans.
Q.
100. In an examination it is required to get 65% of the
aggregate marks to pass. A student gets 522 marks and is declared failed by 7%
marks. What are the maximum aggregate marks a student can get?
(a) 850 (b) 780
(c) 900 (d) Cannot be
determined (e) None of these
Ans:
(c) 900
Explanation:
That is, 65 – 7 =58% of
the maximum marks = 522
So, 1% of the aggregate
marks = 522/58
Therefore, the
aggregate marks = 522 × 100/58 = 900. Ans.
Very very useful blog....
ReplyDeleteI totally agree with this article.
DeleteBest Tnpsc Coaching Centre in Chennai
Best ssc Coaching Centre in Chennai
Best Ias Academy in Chennai
Best Group Exam Coaching Centre in Chennai
Best Bank Exam Coaching Centre in Chennai
a candidate must get 40 to pass in an exam . Preeti gets 250 marks and fails by 70 marks. Find the maximum marks.
ReplyDeleteIn an exam 85% of the candidates passed and and 60 candidates failed.Find the total number candidates appeared in the examination. Please solve it for me
ReplyDelete400
Delete15% = 60
Delete100% = 400.
A man spent 72% of his salary and remaining was his saving. If he saved rs 7200, find his monthly income.solve it for me pls.
ReplyDeleteHis monthly income is Rs.10000
Deletecan u give the solutn plz..
Delete28% = 7200
Delete1% = 7200/28
100% = (7200 *100)/28 = 25,714
Rajan gave 50% of his salary to his wife, 30% to his son and remaining 50,000 to his daughter. Find the amount he had.
ReplyDeleteusefull blog keep posting
ReplyDeleteIn a class, 24 boys are there and one seventh of total are girls. How many students are there in total?
ReplyDeleteBoys = 24.
Delete24 = X - X/7
24 = 6X/7
X = 28.
X = total students.
Rohan's expenditure and saving are in the ratio 5:1. If his salary increased by 25% and his saving increased by 15% then by what percent his expenditure will increase??
ReplyDeleteRohan's expenditure and saving are in the ratio 5:1. If his salary increased by 25% and his saving increased by 15% then by what percent his expenditure will increase??
ReplyDeleteis it 27%
DeleteLet his expenditure = 500.
DeleteSavings = 100.
Salary = Expenditure + savings = 600.
Increased salary = 600 + 25% of 600 = 850.
Increased savings = 100 + 15% of 100 = 115.
Expenditure new = 850 - 115 = 735.
Increased expenditure = 735 - 600 = 135
% increased = (135 *100)/600 = 22.5%.
Thank you so much for sharing this. it is really useful to take a good practice for bank exam. Maths is important factor in all kind of common written exam.
ReplyDeleteWant to know the reason ? check here --> http://www.chennaischoolofbanking.com/why-reasoning-skills-are-important-in-banking-recruitment-exams
thanks for sharing link.
Deletefind the least number of students in exam so that percentage of successful students in exam should be 76.8%? plz tell me how to solve it
ReplyDeleteif a factory of 150 workers 18 were absent on that day.what percent of workers were present on that day?
ReplyDeleteif a factory of 150 workers 18 were absent on that day.what percent of workers were present on that day?
ReplyDeleteThanks for sharing link.
ReplyDeleteSharePoint training in chennai
Thanks for sharing this valuable information.
ReplyDeletejava projects in chennai
dotnet projects in chennai
mba projects in chennai
In a class, 30% of the boys play football, 40% of the remaining play cricKet and the remaining 21 boys paly different other games. How many boys are there in the class ? (1)50 (2)100 (3)48 (4)96 (5) None of these
ReplyDeleteMore Aptitude Questions MCQ
ReplyDeleteAptitude Questions and Answers
Binary Number System
H.C.F and L.C.M of Numbers
Number System
Permutations and Combinations
Probability
Races and Games of Skill
Very nice post here and thanks for it .I always like and such a super contents of these post.Excellent and very cool idea and great content of different kinds of the valuable information's.
ReplyDeleteClick here:
angularjs4 Training in Chennai
Click here:
angularjs5 Training in Chennai
Click here:
Selenium Training in Chennai
Click here:
Aws Training in Chennai
Thanks Admin for sharing such a useful post, I hope it’s useful to many individuals for developing their skill to get good career.
ReplyDeleteClick here:
Microsoft azure training in sollinganallur
Click here:
Microsoft azure training in btm
Awesome..You have clearly explained …Its very useful for me to know about new things..Keep on blogging..
ReplyDeletejava training in chennai | java training in USA
Great thoughts you got there, believe I may possibly try just some of it throughout my daily life.
ReplyDeleteData Science Training in Chennai | Data Science training in anna nagar
Data Science training in chennai | Data science training in Bangalore
Data Science training in marathahalli | Data Science training in btm
I likable the posts and offbeat format you've got here! I’d wish many thanks for sharing your expertise and also the time it took to post!!
ReplyDeleteangularjs Training in chennai
angularjs-Training in pune
angularjs-Training in chennai
angularjs Training in chennai
angularjs-Training in tambaram
angularjs-Training in sholinganallur
I really like your blog. You make it interesting to read and entertaining at the same time. I cant wait to read more from you.
ReplyDeleteinformatica mdm online training
apache spark online training
apache spark online training
devops online training
aws online training
ReplyDeleteYour very own commitment to getting the message throughout came to be rather powerful and have consistently enabled employees just like me to arrive at their desired goals.
Python Training in Chennai| NO.1 Python Training in Chennai
Datascience Training in Chennai | NO.1 Datascience Training in Chennai
RPA Training in Chennai | NO.1 RPA Training in Chennai
DevOps Training in Chennai | NO.1 DevOps Training in Chennai
AWS Training in Chennai | NO.1 AWS Training in Chennai
Existing without the answers to the difficulties you’ve sorted out through this guide is a critical case, as well as the kind which could have badly affected my entire career if I had not discovered your website.
ReplyDeleteBest PHP Training Institute in Chennai|PHP Course in chennai
Best .Net Training Institute in Chennai
Powerbi Training in Chennai
R Programming Training in Chennai
Javascript Training in Chennai
thanks for publishing this wonderful post keep doing on.
ReplyDeleteAngularJS Training in Chennai | AngularJS Training in Anna Nagar | AngularJS Training in OMR | AngularJS Training in Porur | AngularJS Training in Tambaram | AngularJS Training in Velachery
Can't convert object of type java.lang.String to type com.sports.mysports.Blogshare some more.
ReplyDeleteAi & Artificial Intelligence Course in Chennai
PHP Training in Chennai
Ethical Hacking Course in Chennai Blue Prism Training in Chennai
UiPath Training in Chennai
Nice blog,I understood the topic very clearly,And want to study more like this.very useful to me!!!
ReplyDeleteandroid training in chennai
android online training in chennai
android training in bangalore
android training in hyderabad
android Training in coimbatore
android training
android online training
I have been meaning to write something like this on my website and you have given me an idea. Cheers.
ReplyDeleteAngular js Training in Chennai
Angular js Training in Velachery
Angular js Training in Tambaram
Angular js Training in Porur
Angular js Training in Omr
Angular js Training in Annanagar
The questions are very well presented with the answers. This makes me easy to understand the topics and read the questions and answers in a precise way. This is really helpful for my preparation. Thanks for sharing
ReplyDeleteSelenium Training in Chennai
Selenium Training in Velachery
Selenium Training in Tambaram
Selenium Training in Porur
Selenium Training in Omr
Selenium Training in Annanagar
Nice blog,I understood the topic very clearly,And want to study more like this.very useful to me!!!.
ReplyDeleteamazon web services aws training in chennai
microsoft azure course in chennai
workday course in chennai
android course in chennai
ios course in chennai
Good Post! Thank you so much for sharing this pretty post, it was so good to read and useful to improve my knowledge as updated one, keep blogging.
ReplyDeletetally training in chennai
hadoop training in chennai
sap training in chennai
oracle training in chennai
angular js training in chennai
Nice blog,I understood the topic very clearly,And want to study more like this.very useful to me!!!.
ReplyDeleteIELTS Coaching in chennai
German Classes in Chennai
GRE Coaching Classes in Chennai
TOEFL Coaching in Chennai
Spoken english classes in chennai | Communication training
Web design encompasses many different skills and disciplines in the production and maintenance of websites. The different areas of web design include web graphic design; user interface design; authoring, including standardised code and proprietary software; user experience design; and search engine optimization.Java training in chennai
ReplyDeletepython training in chennai
web designing and development training in chennai
selenium training in chennai
digital-marketing training in chennai
Very Informative blog thank you for sharing. Keep sharing.
ReplyDeleteBest software training institute in Chennai. Make your career development the best by learning software courses.
best msbi training institute in chennai
cloud computing courses in chennai
uipath training in chennai
I believe there are many more pleasurable opportunities ahead for
ReplyDeleteindividuals that looked at your site.
unix certification in Chennai
IT training institute in Chennai